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BizzBuzz

New layout (yet again), but i lost the old posts :(

Its 3 o'clock on the last day of my week off from work, and what did I do on the week off?   Programming, so I took a week off from my programming job and did more programming!!. Oh well.

This is not a real post it more of a system test, testing the new features of the site. To do this I have desided to post some Bizz buzz codes (wiki Bizzbuzz page),

Players generally sit in a circle. The player designated to go first says the number "1", and each player thenceforth counts one number in turn. However, any number divisible by three is replaced by the word bizz and any divisible by five by the word buzz. Numbers divisible by both become bizz buzz. A player who hesitates or makes a mistake is either eliminated or must pay a forfeit, such as taking a drink.

Simple yes? Fun for programmers and alcoholics alike :D

The following are code samples, that can be used to solve the BizzBuzz Game, these are not the best answer to the problem, just a quick and dirty response.

Delphi/Pascal

Function BizzBuzz(const endOfTheGame:integer):String;     
     var        output:string;        i:integer; 
begin     
    for i:= 1 to endOfTheGame do 
    begin         
        if ( ((i mod 3) = 0) and ((i mod 5) = 0)) then
        begin     			
            output := output + 'BizzBuzz' + chr(13);
        end 
        else if ((i mod 3) = 0) then
        begin 
            output := output + 'Bizz' + chr(13);     	
        end 
        else if ((i mod 5) = 0) then 
        begin 
            output := output + 'Buzz' + chr(13);     	
        end     	
        else 
            output := output + intToStr(i) + chr(13);     
   end; 

        result := output; 
end;  

PHP

function BizzBuzz($endOfTheGame=100);     
{     
    $output ='';
    
    for ($i= 1;$i <= $endOfTheGame; $i++)
    {         
        if ( (($i % 3) == 0) && (($i % 5) == 0)) then
        {                           
            $output .= $output + 'BizzBuzz' + chr(13);
        } 
        elseif (($i % 3) == 0) then
        { 
            $output .= $output + 'Bizz' + chr(13);        
        } 
        elseif (($i % 5) == 0) then 
        { 
            $output .= $output + 'Buzz' + chr(13);        
        }             
        else 
            $output .=  $i + chr(13);     
        } 

    return = $output; 
}  

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